x ≡ 2 (mod 3)
x ≡ 3 (mod 5)
x ≡ 2 (mod 7)
The Chinese Remainder Theorem states that if integers n₁, n₂, ..., nₖ are pairwise coprime, then for any sequence of integers a₁, a₂, ..., aₖ, there exists a unique solution modulo N = n₁ × n₂ × ... × nₖ.
Given: x ≡ a₁ (mod n₁), x ≡ a₂ (mod n₂), ..., x ≡ aₖ (mod nₖ)
Find: x such that all congruences are satisfied
Cryptography
Speeds up RSA decryption using modular decomposition.
Computing
Reduces large modulo operations to smaller ones.
Number Theory
Solves Diophantine equations efficiently.
For a system like x ≡ 2 (mod 3), x ≡ 3 (mod 5), x ≡ 2 (mod 7):
Step 1: Compute M = 3 × 5 × 7 = 105
Step 2: For each congruence, compute M_i = M / n_i and find its modular inverse
Step 3: Combine: x = Σ(a_i × M_i × M_i⁻¹) mod 105
Result: x ≡ 17 (mod 105) (and any number 17 + 105k is also a solution)